Base | Representation |
---|---|
bin | 11111010101101001110… |
… | …101000100100010101111 |
3 | 21121212200220001010210020 |
4 | 133111221311010202233 |
5 | 240240434324311330 |
6 | 4325155031013223 |
7 | 311406036055410 |
oct | 37255165044257 |
9 | 7555626033706 |
10 | 2153554135215 |
11 | 76035419136a |
12 | 2a9458b0a213 |
13 | 128105255802 |
14 | 76338291807 |
15 | 3b043b0e210 |
hex | 1f569d448af |
2153554135215 has 64 divisors (see below), whose sum is σ = 4246289187840. Its totient is φ = 909919042560.
The previous prime is 2153554135199. The next prime is 2153554135241. The reversal of 2153554135215 is 5125314553512.
It is not a de Polignac number, because 2153554135215 - 24 = 2153554135199 is a prime.
It is a super-3 number, since 3×21535541352153 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 13082544 + ... + 13246133.
It is an arithmetic number, because the mean of its divisors is an integer number (66348268560).
Almost surely, 22153554135215 is an apocalyptic number.
2153554135215 is a deficient number, since it is larger than the sum of its proper divisors (2092735052625).
2153554135215 is a wasteful number, since it uses less digits than its factorization.
2153554135215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26328752.
The product of its digits is 450000, while the sum is 42.
Adding to 2153554135215 its reverse (5125314553512), we get a palindrome (7278868688727).
The spelling of 2153554135215 in words is "two trillion, one hundred fifty-three billion, five hundred fifty-four million, one hundred thirty-five thousand, two hundred fifteen".
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