Base | Representation |
---|---|
bin | 11111010111000111011… |
… | …011001110110111010110 |
3 | 21122000202022210212121222 |
4 | 133113013123032313112 |
5 | 240302143322420204 |
6 | 4330014523410342 |
7 | 311462664214334 |
oct | 37270733166726 |
9 | 7560668725558 |
10 | 2155124420054 |
11 | 760a8a607631 |
12 | 2a98169839b2 |
13 | 1282c5686138 |
14 | 76446a4cb54 |
15 | 3b0d68ddabe |
hex | 1f5c76cedd6 |
2155124420054 has 4 divisors (see below), whose sum is σ = 3232686630084. Its totient is φ = 1077562210026.
The previous prime is 2155124420047. The next prime is 2155124420131. The reversal of 2155124420054 is 4500244215512.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×21551244200542 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2155124419996 and 2155124420023.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 538781105012 + ... + 538781105015.
It is an arithmetic number, because the mean of its divisors is an integer number (808171657521).
Almost surely, 22155124420054 is an apocalyptic number.
2155124420054 is a deficient number, since it is larger than the sum of its proper divisors (1077562210030).
2155124420054 is a wasteful number, since it uses less digits than its factorization.
2155124420054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1077562210029.
The product of its (nonzero) digits is 64000, while the sum is 35.
Adding to 2155124420054 its reverse (4500244215512), we get a palindrome (6655368635566).
The spelling of 2155124420054 in words is "two trillion, one hundred fifty-five billion, one hundred twenty-four million, four hundred twenty thousand, fifty-four".
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