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2201310203102 = 21100655101551
BaseRepresentation
bin100000000010001000010…
…100000000110011011110
321210102222002111202020022
4200002020110000303132
5242031240402444402
64403133513152142
7315016342666133
oct40021024006336
97712862452208
102201310203102
11779630248a6a
122b67663bb652
1312c77615164a
147878898a58a
153c3db4aa2a2
hex20088500cde

2201310203102 has 4 divisors (see below), whose sum is σ = 3301965304656. Its totient is φ = 1100655101550.

The previous prime is 2201310203093. The next prime is 2201310203111. The reversal of 2201310203102 is 2013020131022.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (2201310203093) and next prime (2201310203111).

It is a super-2 number, since 2×22013102031022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550327550774 + ... + 550327550777.

It is an arithmetic number, because the mean of its divisors is an integer number (825491326164).

Almost surely, 22201310203102 is an apocalyptic number.

2201310203102 is a deficient number, since it is larger than the sum of its proper divisors (1100655101554).

2201310203102 is a wasteful number, since it uses less digits than its factorization.

2201310203102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1100655101553.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2201310203102 its reverse (2013020131022), we get a palindrome (4214330334124).

The spelling of 2201310203102 in words is "two trillion, two hundred one billion, three hundred ten million, two hundred three thousand, one hundred two".

Divisors: 1 2 1100655101551 2201310203102