Base | Representation |
---|---|
bin | 1000001100110101… |
… | …0101111101001100 |
3 | 12200102011021212211 |
4 | 2003031111331030 |
5 | 14002014004400 |
6 | 1002233440204 |
7 | 105356565310 |
oct | 20315257514 |
9 | 5612137784 |
10 | 2201313100 |
11 | a2a647128 |
12 | 515270064 |
13 | 2910a123c |
14 | 16c4ddb40 |
15 | cd3cadba |
hex | 83355f4c |
2201313100 has 144 divisors (see below), whose sum is σ = 5731188736. Its totient is φ = 717984000.
The previous prime is 2201313091. The next prime is 2201313133. The reversal of 2201313100 is 13131022.
2201313100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×22013131002 = 9691558728463220000, which contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1322869 + ... + 1324531.
Almost surely, 22201313100 is an apocalyptic number.
2201313100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2201313100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2865594368).
2201313100 is an abundant number, since it is smaller than the sum of its proper divisors (3529875636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2201313100 is a wasteful number, since it uses less digits than its factorization.
2201313100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1776 (or 1769 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
The square root of 2201313100 is about 46918.1532032112. The cubic root of 2201313100 is about 1300.8501539674.
Adding to 2201313100 its reverse (13131022), we get a palindrome (2214444122).
It can be divided in two parts, 2 and 201313100, that added together give a palindrome (201313102).
The spelling of 2201313100 in words is "two billion, two hundred one million, three hundred thirteen thousand, one hundred".
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