Base | Representation |
---|---|
bin | 1000001100110101… |
… | …1010110101101100 |
3 | 12200102012022022120 |
4 | 2003031122311230 |
5 | 14002020124400 |
6 | 1002234112540 |
7 | 105360010521 |
oct | 20315326554 |
9 | 5612168276 |
10 | 2201333100 |
11 | a2a66015a |
12 | 51527b750 |
13 | 2910aa385 |
14 | 16c507148 |
15 | cd3d1ca0 |
hex | 8335ad6c |
2201333100 has 36 divisors (see below), whose sum is σ = 6369191304. Its totient is φ = 587022080.
The previous prime is 2201333081. The next prime is 2201333107. The reversal of 2201333100 is 13331022.
2201333100 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×22013331002 = 9691734834311220000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 2201333100.
It is not an unprimeable number, because it can be changed into a prime (2201333107) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3668589 + ... + 3669188.
Almost surely, 22201333100 is an apocalyptic number.
2201333100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2201333100 is an abundant number, since it is smaller than the sum of its proper divisors (4167858204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2201333100 is a wasteful number, since it uses less digits than its factorization.
2201333100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7337794 (or 7337787 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 15.
The square root of 2201333100 is about 46918.3663398461. The cubic root of 2201333100 is about 1300.8540935742.
Adding to 2201333100 its reverse (13331022), we get a palindrome (2214664122).
It can be divided in two parts, 2 and 201333100, that added together give a palindrome (201333102).
The spelling of 2201333100 in words is "two billion, two hundred one million, three hundred thirty-three thousand, one hundred".
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