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221110010113 is a prime number
BaseRepresentation
bin1100110111101100101…
…1110000000100000001
3210010201112111022100211
43031323023300010001
512110313130310423
6245324310514121
721655212034666
oct3157313600401
9703645438324
10221110010113
1185854922253
1236a29365941
1317b09970b15
14a9b798da6d
155b418a210d
hex337b2f0101

221110010113 has 2 divisors, whose sum is σ = 221110010114. Its totient is φ = 221110010112.

The previous prime is 221110010021. The next prime is 221110010129. The reversal of 221110010113 is 311010011122.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124840675584 + 96269334529 = 353328^2 + 310273^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-221110010113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 221110010093 and 221110010102.

It is not a weakly prime, because it can be changed into another prime (221110017113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110555005056 + 110555005057.

It is an arithmetic number, because the mean of its divisors is an integer number (110555005057).

Almost surely, 2221110010113 is an apocalyptic number.

It is an amenable number.

221110010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

221110010113 is an equidigital number, since it uses as much as digits as its factorization.

221110010113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 221110010113 its reverse (311010011122), we get a palindrome (532120021235).

The spelling of 221110010113 in words is "two hundred twenty-one billion, one hundred ten million, ten thousand, one hundred thirteen".