Base | Representation |
---|---|
bin | 100000001011011110111… |
… | …110011101000101010111 |
3 | 21211101220001212210021110 |
4 | 200023132332131011113 |
5 | 242212323122313101 |
6 | 4411514304550103 |
7 | 315523262514363 |
oct | 40133676350527 |
9 | 7741801783243 |
10 | 2211354104151 |
11 | 782914818535 |
12 | 2b86aa022333 |
13 | 1306b6c7016a |
14 | 7905c89a2a3 |
15 | 3c7c813acd6 |
hex | 202def9d157 |
2211354104151 has 4 divisors (see below), whose sum is σ = 2948472138872. Its totient is φ = 1474236069432.
The previous prime is 2211354104119. The next prime is 2211354104243. The reversal of 2211354104151 is 1514014531122.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2211354104151 - 25 = 2211354104119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2211352104151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 368559017356 + ... + 368559017361.
It is an arithmetic number, because the mean of its divisors is an integer number (737118034718).
Almost surely, 22211354104151 is an apocalyptic number.
2211354104151 is a deficient number, since it is larger than the sum of its proper divisors (737118034721).
2211354104151 is an equidigital number, since it uses as much as digits as its factorization.
2211354104151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 737118034720.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 2211354104151 its reverse (1514014531122), we get a palindrome (3725368635273).
The spelling of 2211354104151 in words is "two trillion, two hundred eleven billion, three hundred fifty-four million, one hundred four thousand, one hundred fifty-one".
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