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22120433 is a prime number
BaseRepresentation
bin101010001100…
…0011111110001
31112121211112022
41110120133301
521130323213
62110041225
7356010026
oct124303761
945554468
1022120433
1111539455
1274a9215
13477661a
142d1b54d
151e1e308
hex15187f1

22120433 has 2 divisors, whose sum is σ = 22120434. Its totient is φ = 22120432.

The previous prime is 22120393. The next prime is 22120459. The reversal of 22120433 is 33402122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13162384 + 8958049 = 3628^2 + 2993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-22120433 is a prime.

It is a super-2 number, since 2×221204332 = 978627112214978, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (22120493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11060216 + 11060217.

It is an arithmetic number, because the mean of its divisors is an integer number (11060217).

Almost surely, 222120433 is an apocalyptic number.

It is an amenable number.

22120433 is a deficient number, since it is larger than the sum of its proper divisors (1).

22120433 is an equidigital number, since it uses as much as digits as its factorization.

22120433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 22120433 is about 4703.2364388791. The cubic root of 22120433 is about 280.7143029060.

Adding to 22120433 its reverse (33402122), we get a palindrome (55522555).

The spelling of 22120433 in words is "twenty-two million, one hundred twenty thousand, four hundred thirty-three".