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22314002531 is a prime number
BaseRepresentation
bin10100110010000001…
…001010100001100011
32010121002201202222012
4110302001022201203
5331144341040111
614130110303135
71416650614652
oct246201124143
963532652865
1022314002531
119510744407
1243a8ab7aab
132147c133c2
14111975b199
158a8ea648b
hex53204a863

22314002531 has 2 divisors, whose sum is σ = 22314002532. Its totient is φ = 22314002530.

The previous prime is 22314002479. The next prime is 22314002533. The reversal of 22314002531 is 13520041322.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 22314002531 - 26 = 22314002467 is a prime.

It is a super-3 number, since 3×223140025313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 22314002533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 22314002497 and 22314002506.

It is not a weakly prime, because it can be changed into another prime (22314002533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11157001265 + 11157001266.

It is an arithmetic number, because the mean of its divisors is an integer number (11157001266).

Almost surely, 222314002531 is an apocalyptic number.

22314002531 is a deficient number, since it is larger than the sum of its proper divisors (1).

22314002531 is an equidigital number, since it uses as much as digits as its factorization.

22314002531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 22314002531 its reverse (13520041322), we get a palindrome (35834043853).

The spelling of 22314002531 in words is "twenty-two billion, three hundred fourteen million, two thousand, five hundred thirty-one".