Base | Representation |
---|---|
bin | 100000100111001000000… |
… | …010011011100001011001 |
3 | 21221020111111220211010211 |
4 | 200213020002123201121 |
5 | 243204114203311213 |
6 | 4433303345011121 |
7 | 320623625023645 |
oct | 40471002334131 |
9 | 7836444824124 |
10 | 2241034041433 |
11 | 794465324720 |
12 | 3023b1923aa1 |
13 | 133436c31625 |
14 | 7a6765cbc25 |
15 | 3d463ae153d |
hex | 209c809b859 |
2241034041433 has 64 divisors (see below), whose sum is σ = 2771848138752. Its totient is φ = 1786314055680.
The previous prime is 2241034041391. The next prime is 2241034041461. The reversal of 2241034041433 is 3341404301422.
It is a de Polignac number, because none of the positive numbers 2k-2241034041433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2241034041395 and 2241034041404.
It is not an unprimeable number, because it can be changed into a prime (2241034041833) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 65267716 + ... + 65302042.
It is an arithmetic number, because the mean of its divisors is an integer number (43310127168).
Almost surely, 22241034041433 is an apocalyptic number.
2241034041433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2241034041433 is a deficient number, since it is larger than the sum of its proper divisors (530814097319).
2241034041433 is a wasteful number, since it uses less digits than its factorization.
2241034041433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34774.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 2241034041433 its reverse (3341404301422), we get a palindrome (5582438342855).
The spelling of 2241034041433 in words is "two trillion, two hundred forty-one billion, thirty-four million, forty-one thousand, four hundred thirty-three".
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