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2244131424287 is a prime number
BaseRepresentation
bin100000101010000000101…
…010000000100000011111
321221112111101012011122022
4200222000222000200133
5243231440121034122
64434534552410355
7321063445241444
oct40520052004037
97845441164568
102244131424287
11795804759265
12302b170a69bb
1313380b85134c
147a88bb039cb
153d5959be642
hex20a80a8081f

2244131424287 has 2 divisors, whose sum is σ = 2244131424288. Its totient is φ = 2244131424286.

The previous prime is 2244131424257. The next prime is 2244131424289. The reversal of 2244131424287 is 7824241314422.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2244131424287 - 228 = 2243862988831 is a prime.

It is a super-2 number, since 2×22441314242872 (a number of 26 digits) contains 22 as substring.

Together with 2244131424289, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2244131424289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1122065712143 + 1122065712144.

It is an arithmetic number, because the mean of its divisors is an integer number (1122065712144).

Almost surely, 22244131424287 is an apocalyptic number.

2244131424287 is a deficient number, since it is larger than the sum of its proper divisors (1).

2244131424287 is an equidigital number, since it uses as much as digits as its factorization.

2244131424287 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 688128, while the sum is 44.

The spelling of 2244131424287 in words is "two trillion, two hundred forty-four billion, one hundred thirty-one million, four hundred twenty-four thousand, two hundred eighty-seven".