Base | Representation |
---|---|
bin | 110011001010010110000111… |
… | …011101001011100111000011 |
3 | 1002111200212112100221211122201 |
4 | 303022112013131023213003 |
5 | 213443041132421302120 |
6 | 2114320434251414031 |
7 | 65252350061521024 |
oct | 6312260735134703 |
9 | 1074625470854581 |
10 | 225011314244035 |
11 | 65771842948950 |
12 | 212a0849a54317 |
13 | 98726256a8817 |
14 | 3d7c86a138c4b |
15 | 1b030d9aaa40a |
hex | cca58774b9c3 |
225011314244035 has 16 divisors (see below), whose sum is σ = 294648749267040. Its totient is φ = 163595434762240.
The previous prime is 225011314244023. The next prime is 225011314244071. The reversal of 225011314244035 is 530442413110522.
It is not a de Polignac number, because 225011314244035 - 239 = 224461558430147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 225011314243985 and 225011314244003.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 614282932 + ... + 614649121.
It is an arithmetic number, because the mean of its divisors is an integer number (18415546829190).
Almost surely, 2225011314244035 is an apocalyptic number.
225011314244035 is a deficient number, since it is larger than the sum of its proper divisors (69637435023005).
225011314244035 is a wasteful number, since it uses less digits than its factorization.
225011314244035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1228935398.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 225011314244035 its reverse (530442413110522), we get a palindrome (755453727354557).
The spelling of 225011314244035 in words is "two hundred twenty-five trillion, eleven billion, three hundred fourteen million, two hundred forty-four thousand, thirty-five".
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