Base | Representation |
---|---|
bin | 10101000110111100… |
… | …100111000001000111 |
3 | 2011111120102220101022 |
4 | 111012330213001013 |
5 | 332404233130210 |
6 | 14225012221355 |
7 | 1431443266241 |
oct | 250674470107 |
9 | 64446386338 |
10 | 22665130055 |
11 | 9680969747 |
12 | 448660a85b |
13 | 21a28a2879 |
14 | 115023d091 |
15 | 8c9c14155 |
hex | 546f27047 |
22665130055 has 4 divisors (see below), whose sum is σ = 27198156072. Its totient is φ = 18132104040.
The previous prime is 22665130027. The next prime is 22665130067. The reversal of 22665130055 is 55003156622.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 22665130055 - 216 = 22665064519 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22665129997 and 22665130024.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2266513001 + ... + 2266513010.
It is an arithmetic number, because the mean of its divisors is an integer number (6799539018).
Almost surely, 222665130055 is an apocalyptic number.
22665130055 is a deficient number, since it is larger than the sum of its proper divisors (4533026017).
22665130055 is an equidigital number, since it uses as much as digits as its factorization.
22665130055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4533026016.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 22665130055 its reverse (55003156622), we get a palindrome (77668286677).
The spelling of 22665130055 in words is "twenty-two billion, six hundred sixty-five million, one hundred thirty thousand, fifty-five".
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