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23000035 = 54600007
BaseRepresentation
bin101011110111…
…1001111100011
31121021112010011
41113233033203
521342000120
62140545351
7366332332
oct127571743
947245104
1023000035
1111a8a2a3
127852257
1349c3ab6
1430a9d19
152044c5a
hex15ef3e3

23000035 has 4 divisors (see below), whose sum is σ = 27600048. Its totient is φ = 18400024.

The previous prime is 23000027. The next prime is 23000059. The reversal of 23000035 is 53000032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23000035 - 23 = 23000027 is a prime.

It is a super-2 number, since 2×230000352 = 1058003220002450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 22999979 and 23000024.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2299999 + ... + 2300008.

It is an arithmetic number, because the mean of its divisors is an integer number (6900012).

Almost surely, 223000035 is an apocalyptic number.

23000035 is a deficient number, since it is larger than the sum of its proper divisors (4600013).

23000035 is an equidigital number, since it uses as much as digits as its factorization.

23000035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4600012.

The product of its (nonzero) digits is 90, while the sum is 13.

The square root of 23000035 is about 4795.8351723136. The cubic root of 23000035 is about 284.3868422392.

Adding to 23000035 its reverse (53000032), we get a palindrome (76000067).

The spelling of 23000035 in words is "twenty-three million, thirty-five", and thus it is an aban number and an uban number.

Divisors: 1 5 4600007 23000035