230113111 has 2 divisors, whose sum is σ = 230113112. Its totient is φ = 230113110.

The previous prime is 230113109. The next prime is 230113151. The reversal of 230113111 is 111311032.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 230113111 - 2¹ = 230113109 is a prime.

Together with 230113109, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 230113091 and 230113100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (230113151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115056555 + 115056556.

It is an arithmetic number, because the mean of its divisors is an integer number (115056556).

Almost surely, 2^230113111 is an apocalyptic number.

230113111 is a deficient number, since it is larger than the sum of its proper divisors (1).

230113111 is an equidigital number, since it uses as much as digits as its factorization.

230113111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 230113111 is about 15169.4795889642. The cubic root of 230113111 is about 612.7929891336.

Adding to 230113111 its reverse (111311032), we get a palindrome (341424143).

The spelling of 230113111 in words is "two hundred thirty million, one hundred thirteen thousand, one hundred eleven".