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23100120000 = 26335473293
BaseRepresentation
bin10101100000110111…
…111101101111000000
32012121212221200102000
4111200313331233000
5334302112320000
614340111424000
71445304531426
oct254067755700
965555850360
1023100120000
119884463071
124588225000
132241a45479
141191d11116
15902eda000
hex560dfdbc0

23100120000 has 560 divisors, whose sum is σ = 86316494880. Its totient is φ = 6054912000.

The previous prime is 23100119993. The next prime is 23100120007. The reversal of 23100120000 is 2100132.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (23100119993) and next prime (23100120007).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23100120007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 78839854 + ... + 78840146.

It is an arithmetic number, because the mean of its divisors is an integer number (154136598).

Almost surely, 223100120000 is an apocalyptic number.

23100120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 23100120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (43158247440).

23100120000 is an abundant number, since it is smaller than the sum of its proper divisors (63216374880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

23100120000 is an equidigital number, since it uses as much as digits as its factorization.

23100120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 407 (or 376 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 23100120000 its reverse (2100132), we get a palindrome (23102220132).

It can be divided in two parts, 231001 and 20000, that added together give a square (251001 = 5012).

The spelling of 23100120000 in words is "twenty-three billion, one hundred million, one hundred twenty thousand".