Base | Representation |
---|---|
bin | 1010100000010111011110… |
… | …00001101101010010000101 |
3 | 10000210120012002121221000011 |
4 | 11100023233001231102011 |
5 | 11012002100121221013 |
6 | 121045023115350221 |
7 | 4603042425446041 |
oct | 520135701552205 |
9 | 100716162557004 |
10 | 23102344320133 |
11 | 73a7716101271 |
12 | 2711480452371 |
13 | cb7707215540 |
14 | 59c23369d021 |
15 | 2a0e2953cc3d |
hex | 1502ef06d485 |
23102344320133 has 8 divisors (see below), whose sum is σ = 24903815469176. Its totient is φ = 21304354276800.
The previous prime is 23102344320103. The next prime is 23102344320163. The reversal of 23102344320133 is 33102344320132.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (23102344320103) and next prime (23102344320163).
It can be written as a sum of positive squares in 4 ways, for example, as 5762390648004 + 17339953672129 = 2400498^2 + 4164127^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23102344320133 - 213 = 23102344311941 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23102344320095 and 23102344320104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23102344320103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 870262638 + ... + 870289183.
It is an arithmetic number, because the mean of its divisors is an integer number (3112976933647).
Almost surely, 223102344320133 is an apocalyptic number.
It is an amenable number.
23102344320133 is a deficient number, since it is larger than the sum of its proper divisors (1801471149043).
23102344320133 is a wasteful number, since it uses less digits than its factorization.
23102344320133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1740552855.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 23102344320133 its reverse (33102344320132), we get a palindrome (56204688640265).
Subtracting 23102344320133 from its reverse (33102344320132), we obtain a palindrome (9999999999999).
The spelling of 23102344320133 in words is "twenty-three trillion, one hundred two billion, three hundred forty-four million, three hundred twenty thousand, one hundred thirty-three".
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