Base | Representation |
---|---|
bin | 100001101000011010001… |
… | …011001011011001001011 |
3 | 22011221102201201212011211 |
4 | 201220122023023121023 |
5 | 300331144133334430 |
6 | 4525415201433551 |
7 | 325654664662033 |
oct | 41503213133113 |
9 | 8157381655154 |
10 | 2311131543115 |
11 | 81116656119a |
12 | 313ab533b8b7 |
13 | 139c28626585 |
14 | 7dc061448c3 |
15 | 401b7a6172a |
hex | 21a1a2cb64b |
2311131543115 has 4 divisors (see below), whose sum is σ = 2773357851744. Its totient is φ = 1848905234488.
The previous prime is 2311131543103. The next prime is 2311131543131. The reversal of 2311131543115 is 5113451311132.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2311131543115 - 217 = 2311131412043 is a prime.
It is a super-2 number, since 2×23111315431152 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231113154307 + ... + 231113154316.
It is an arithmetic number, because the mean of its divisors is an integer number (693339462936).
Almost surely, 22311131543115 is an apocalyptic number.
2311131543115 is a deficient number, since it is larger than the sum of its proper divisors (462226308629).
2311131543115 is an equidigital number, since it uses as much as digits as its factorization.
2311131543115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 462226308628.
The product of its digits is 5400, while the sum is 31.
Adding to 2311131543115 its reverse (5113451311132), we get a palindrome (7424582854247).
The spelling of 2311131543115 in words is "two trillion, three hundred eleven billion, one hundred thirty-one million, five hundred forty-three thousand, one hundred fifteen".
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