Base | Representation |
---|---|
bin | 10101100001100101… |
… | …101101000011011111 |
3 | 2012122201111212000022 |
4 | 111201211231003133 |
5 | 334313200012203 |
6 | 14341220422355 |
7 | 1445511460532 |
oct | 254145550337 |
9 | 65581455008 |
10 | 23112110303 |
11 | 9890202607 |
12 | 45902479bb |
13 | 2244382c19 |
14 | 1193752a19 |
15 | 9040a7a38 |
hex | 56196d0df |
23112110303 has 4 divisors (see below), whose sum is σ = 24116984688. Its totient is φ = 22107235920.
The previous prime is 23112110299. The next prime is 23112110327. The reversal of 23112110303 is 30301121132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23112110303 - 22 = 23112110299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23112110003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502437158 + ... + 502437203.
It is an arithmetic number, because the mean of its divisors is an integer number (6029246172).
Almost surely, 223112110303 is an apocalyptic number.
23112110303 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
23112110303 is a deficient number, since it is larger than the sum of its proper divisors (1004874385).
23112110303 is a wasteful number, since it uses less digits than its factorization.
23112110303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1004874384.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 23112110303 its reverse (30301121132), we get a palindrome (53413231435).
The spelling of 23112110303 in words is "twenty-three billion, one hundred twelve million, one hundred ten thousand, three hundred three".
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