Base | Representation |
---|---|
bin | 110100100110000001010001… |
… | …110100000111111110010100 |
3 | 1010100000010110110012111202020 |
4 | 310212001101310013332110 |
5 | 220304300144103441040 |
6 | 2135542511115013140 |
7 | 66502451316205224 |
oct | 6446012164077624 |
9 | 1110003413174666 |
10 | 231311131312020 |
11 | 677805553a2011 |
12 | 21b39791a3a1b0 |
13 | 9c0b7139a7906 |
14 | 4119738a4c084 |
15 | 1bb1e00119cd0 |
hex | d26051d07f94 |
231311131312020 has 48 divisors (see below), whose sum is σ = 647671925557440. Its totient is φ = 61682896170496.
The previous prime is 231311131311913. The next prime is 231311131312043. The reversal of 231311131312020 is 20213131113132.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67040671 + ... + 70406489.
It is an arithmetic number, because the mean of its divisors is an integer number (13493165115780).
Almost surely, 2231311131312020 is an apocalyptic number.
231311131312020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
231311131312020 is an abundant number, since it is smaller than the sum of its proper divisors (416360794245420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
231311131312020 is a wasteful number, since it uses less digits than its factorization.
231311131312020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4511224 (or 4511222 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 231311131312020 its reverse (20213131113132), we get a palindrome (251524262425152).
The spelling of 231311131312020 in words is "two hundred thirty-one trillion, three hundred eleven billion, one hundred thirty-one million, three hundred twelve thousand, twenty".
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