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23145122433 = 323335436557
BaseRepresentation
bin10101100011100011…
…101000101010000001
32012202000122001010210
4111203203220222001
5334400122404213
614344400144333
71446362203026
oct254343505201
965660561123
1023145122433
1198a7900064
12459b3080a9
13224b170c24
141197ca754d
15906e290c3
hex5638e8a81

23145122433 has 8 divisors (see below), whose sum is σ = 32201909568. Its totient is φ = 14759208464.

The previous prime is 23145122431. The next prime is 23145122437. The reversal of 23145122433 is 33422154132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23145122433 - 21 = 23145122431 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23145122433.

It is not an unprimeable number, because it can be changed into a prime (23145122431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 167718210 + ... + 167718347.

It is an arithmetic number, because the mean of its divisors is an integer number (4025238696).

Almost surely, 223145122433 is an apocalyptic number.

23145122433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

23145122433 is a deficient number, since it is larger than the sum of its proper divisors (9056787135).

23145122433 is a wasteful number, since it uses less digits than its factorization.

23145122433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 335436583.

The product of its digits is 17280, while the sum is 30.

Adding to 23145122433 its reverse (33422154132), we get a palindrome (56567276565).

The spelling of 23145122433 in words is "twenty-three billion, one hundred forty-five million, one hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 3 23 69 335436557 1006309671 7715040811 23145122433