Base | Representation |
---|---|
bin | 100001101011100011101… |
… | …100010001101100100111 |
3 | 22012021011100111012221210 |
4 | 201223203230101230213 |
5 | 300410110141040403 |
6 | 4531134454042503 |
7 | 326134530064413 |
oct | 41534354215447 |
9 | 8167140435853 |
10 | 2314512440103 |
11 | 812640a2a136 |
12 | 314699649433 |
13 | 13a346bc1336 |
14 | 8004717bd43 |
15 | 40314793b03 |
hex | 21ae3b11b27 |
2314512440103 has 4 divisors (see below), whose sum is σ = 3086016586808. Its totient is φ = 1543008293400.
The previous prime is 2314512440029. The next prime is 2314512440137. The reversal of 2314512440103 is 3010442154132.
2314512440103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2314512440103 - 212 = 2314512436007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2314512340103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385752073348 + ... + 385752073353.
It is an arithmetic number, because the mean of its divisors is an integer number (771504146702).
Almost surely, 22314512440103 is an apocalyptic number.
2314512440103 is a deficient number, since it is larger than the sum of its proper divisors (771504146705).
2314512440103 is an equidigital number, since it uses as much as digits as its factorization.
2314512440103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 771504146704.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 2314512440103 its reverse (3010442154132), we get a palindrome (5324954594235).
The spelling of 2314512440103 in words is "two trillion, three hundred fourteen billion, five hundred twelve million, four hundred forty thousand, one hundred three".
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