Base | Representation |
---|---|
bin | 10101100100011100… |
… | …100101001011101101 |
3 | 2012210001201110110221 |
4 | 111210130211023231 |
5 | 334412433103123 |
6 | 14350052131341 |
7 | 1446633115603 |
oct | 254434451355 |
9 | 65701643427 |
10 | 23160050413 |
11 | 9905276735 |
12 | 45a4306b51 |
13 | 2251299856 |
14 | 1199c71873 |
15 | 9083c725d |
hex | 5647252ed |
23160050413 has 2 divisors, whose sum is σ = 23160050414. Its totient is φ = 23160050412.
The previous prime is 23160050411. The next prime is 23160050467. The reversal of 23160050413 is 31405006132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 21327097444 + 1832952969 = 146038^2 + 42813^2 .
It is a cyclic number.
It is not a de Polignac number, because 23160050413 - 21 = 23160050411 is a prime.
Together with 23160050411, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23160050411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11580025206 + 11580025207.
It is an arithmetic number, because the mean of its divisors is an integer number (11580025207).
Almost surely, 223160050413 is an apocalyptic number.
It is an amenable number.
23160050413 is a deficient number, since it is larger than the sum of its proper divisors (1).
23160050413 is an equidigital number, since it uses as much as digits as its factorization.
23160050413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 23160050413 its reverse (31405006132), we get a palindrome (54565056545).
The spelling of 23160050413 in words is "twenty-three billion, one hundred sixty million, fifty thousand, four hundred thirteen".
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