Base | Representation |
---|---|
bin | 100001110000110001011… |
… | …001110110011110000011 |
3 | 22012210121112112200212022 |
4 | 201300301121312132003 |
5 | 301003041431401011 |
6 | 4533502214552055 |
7 | 326423342545064 |
oct | 41606131663603 |
9 | 8183545480768 |
10 | 2320111200131 |
11 | 814a5431843a |
12 | 3157a066862b |
13 | 13aa29b032aa |
14 | 8041898256b |
15 | 405410708db |
hex | 21c31676783 |
2320111200131 has 2 divisors, whose sum is σ = 2320111200132. Its totient is φ = 2320111200130.
The previous prime is 2320111200079. The next prime is 2320111200133. The reversal of 2320111200131 is 1310021110232.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2320111200131 is a prime.
It is a super-2 number, since 2×23201112001312 (a number of 26 digits) contains 22 as substring.
Together with 2320111200133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2320111200133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160055600065 + 1160055600066.
It is an arithmetic number, because the mean of its divisors is an integer number (1160055600066).
Almost surely, 22320111200131 is an apocalyptic number.
2320111200131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2320111200131 is an equidigital number, since it uses as much as digits as its factorization.
2320111200131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2320111200131 its reverse (1310021110232), we get a palindrome (3630132310363).
The spelling of 2320111200131 in words is "two trillion, three hundred twenty billion, one hundred eleven million, two hundred thousand, one hundred thirty-one".
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