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23212421413 is a prime number
BaseRepresentation
bin10101100111100100…
…010111000100100101
32012220201021011222121
4111213210113010211
5340014334441123
614355202425541
71451140216666
oct254744270445
965821234877
1023212421413
119931896855
1245b99622b1
13225c0a51cc
1411a2bc536d
1590ccbe75d
hex567917125

23212421413 has 2 divisors, whose sum is σ = 23212421414. Its totient is φ = 23212421412.

The previous prime is 23212421411. The next prime is 23212421497. The reversal of 23212421413 is 31412421232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19155113604 + 4057307809 = 138402^2 + 63697^2 .

It is a cyclic number.

It is not a de Polignac number, because 23212421413 - 21 = 23212421411 is a prime.

Together with 23212421411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23212421411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606210706 + 11606210707.

It is an arithmetic number, because the mean of its divisors is an integer number (11606210707).

Almost surely, 223212421413 is an apocalyptic number.

It is an amenable number.

23212421413 is a deficient number, since it is larger than the sum of its proper divisors (1).

23212421413 is an equidigital number, since it uses as much as digits as its factorization.

23212421413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 25.

Adding to 23212421413 its reverse (31412421232), we get a palindrome (54624842645).

The spelling of 23212421413 in words is "twenty-three billion, two hundred twelve million, four hundred twenty-one thousand, four hundred thirteen".