Base | Representation |
---|---|
bin | 1101100100011110100… |
… | …0011010100111011100 |
3 | 211021202020020121220120 |
4 | 3121013220122213130 |
5 | 12304422240323400 |
6 | 255033133114540 |
7 | 22562115253440 |
oct | 3310750324734 |
9 | 737666217816 |
10 | 233130011100 |
11 | 8a9628a4968 |
12 | 39222928a50 |
13 | 18ca3cb933c |
14 | b3d80d6820 |
15 | 60e6c73ca0 |
hex | 3647a1a9dc |
233130011100 has 144 divisors (see below), whose sum is σ = 797465625600. Its totient is φ = 51449368320.
The previous prime is 233130011099. The next prime is 233130011111. The reversal of 233130011100 is 1110031332.
It is a super-2 number, since 2×2331300111002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 233130011100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1853140 + ... + 1974939.
Almost surely, 2233130011100 is an apocalyptic number.
233130011100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
233130011100 is an abundant number, since it is smaller than the sum of its proper divisors (564335614500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
233130011100 is a wasteful number, since it uses less digits than its factorization.
233130011100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3828132 (or 3828125 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 233130011100 its reverse (1110031332), we get a palindrome (234240042432).
The spelling of 233130011100 in words is "two hundred thirty-three billion, one hundred thirty million, eleven thousand, one hundred".
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