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23433125011 = 193733333037
BaseRepresentation
bin10101110100101110…
…010001110010010011
32020111002120002101221
4111310232101302103
5340442340000021
614433125105511
71456460163502
oct256456216223
966432502357
1023433125011
119a3542a71a
12465b858297
132295a2ac5a
1411c4236839
15922368241
hex574b91c93

23433125011 has 8 divisors (see below), whose sum is σ = 25333108880. Its totient is φ = 21599807328.

The previous prime is 23433124951. The next prime is 23433125033. The reversal of 23433125011 is 11052133432.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23433125011 - 229 = 22896254099 is a prime.

It is a super-2 number, since 2×234331250112 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (23433105011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16665816 + ... + 16667221.

It is an arithmetic number, because the mean of its divisors is an integer number (3166638610).

Almost surely, 223433125011 is an apocalyptic number.

23433125011 is a deficient number, since it is larger than the sum of its proper divisors (1899983869).

23433125011 is a wasteful number, since it uses less digits than its factorization.

23433125011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33333093.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 23433125011 its reverse (11052133432), we get a palindrome (34485258443).

The spelling of 23433125011 in words is "twenty-three billion, four hundred thirty-three million, one hundred twenty-five thousand, eleven".

Divisors: 1 19 37 703 33333037 633327703 1233322369 23433125011