Search a number
-
+
23500115 = 54700023
BaseRepresentation
bin101100110100…
…1010101010011
31122012221002122
41121221111103
522004000430
62155404455
7403514312
oct131512523
948187078
1023500115
11122a0a91
127a5372b
134b3a5c2
14319a279
1520e2ee5
hex1669553

23500115 has 4 divisors (see below), whose sum is σ = 28200144. Its totient is φ = 18800088.

The previous prime is 23500091. The next prime is 23500117. The reversal of 23500115 is 51100532.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23500115 - 214 = 23483731 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23500093 and 23500102.

It is not an unprimeable number, because it can be changed into a prime (23500117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350007 + ... + 2350016.

It is an arithmetic number, because the mean of its divisors is an integer number (7050036).

Almost surely, 223500115 is an apocalyptic number.

23500115 is a deficient number, since it is larger than the sum of its proper divisors (4700029).

23500115 is an equidigital number, since it uses as much as digits as its factorization.

23500115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4700028.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 23500115 is about 4847.6917187461. The cubic root of 23500115 is about 286.4331830290.

Adding to 23500115 its reverse (51100532), we get a palindrome (74600647).

The spelling of 23500115 in words is "twenty-three million, five hundred thousand, one hundred fifteen".

Divisors: 1 5 4700023 23500115