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2412300055 = 511894611069
BaseRepresentation
bin1000111111001000…
…1100011100010111
320020010011112120111
42033302030130113
514420022100210
61035211543451
7113531132524
oct21762143427
96203145514
102412300055
111028753810
12573a5ab87
132c5a043a9
1418c54214b
15e1ba588a
hex8fc8c717

2412300055 has 32 divisors (see below), whose sum is σ = 3203323200. Its totient is φ = 1729305600.

The previous prime is 2412300041. The next prime is 2412300073. The reversal of 2412300055 is 5500032142.

It is not a de Polignac number, because 2412300055 - 231 = 264816407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2412299999 and 2412300035.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2256061 + ... + 2257129.

It is an arithmetic number, because the mean of its divisors is an integer number (100103850).

Almost surely, 22412300055 is an apocalyptic number.

2412300055 is a deficient number, since it is larger than the sum of its proper divisors (791023145).

2412300055 is a wasteful number, since it uses less digits than its factorization.

2412300055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1635.

The product of its (nonzero) digits is 1200, while the sum is 22.

The square root of 2412300055 is about 49115.1713322879. The cubic root of 2412300055 is about 1341.1492433404.

Adding to 2412300055 its reverse (5500032142), we get a palindrome (7912332197).

The spelling of 2412300055 in words is "two billion, four hundred twelve million, three hundred thousand, fifty-five".

Divisors: 1 5 11 55 89 445 461 979 1069 2305 4895 5071 5345 11759 25355 41029 58795 95141 205145 451319 475705 492809 1046551 2256595 2464045 5232755 5420899 27104495 43860001 219300005 482460011 2412300055