2413043311432 has 32 divisors (see below), whose sum is σ = 5084338754880. Its totient is φ = 1065290022720.

The previous prime is 2413043311429. The next prime is 2413043311457. The reversal of 2413043311432 is 2341133403142.

It is a junction number, because it is equal to n+sod(n) for n = 2413043311394 and 2413043311403.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 504396294 + ... + 504401077.

It is an arithmetic number, because the mean of its divisors is an integer number (158885586090).

Almost surely, 2^{2413043311432} is an apocalyptic number.

It is an amenable number.

2413043311432 is an abundant number, since it is smaller than the sum of its proper divisors (2671295443448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2413043311432 is a wasteful number, since it uses less digits than its factorization.

2413043311432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008797413 (or 1008797409 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 2413043311432 its reverse (2341133403142), we get a palindrome (4754176714574).

The spelling of 2413043311432 in words is "two trillion, four hundred thirteen billion, forty-three million, three hundred eleven thousand, four hundred thirty-two".