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24144203113117 is a prime number
BaseRepresentation
bin1010111110101100000101…
…01001100110001010011101
310011111011102000202100121021
411133112002221212022131
511131034311444104432
6123203405505204141
75041234601202313
oct537260251461235
9104434360670537
1024144203113117
11776955424594a
12285b384930651
131061a3369a129
145d682b0d20b3
152bd0a5a59697
hex15f582a6629d

24144203113117 has 2 divisors, whose sum is σ = 24144203113118. Its totient is φ = 24144203113116.

The previous prime is 24144203112941. The next prime is 24144203113123. The reversal of 24144203113117 is 71131130244142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18091845409401 + 6052357703716 = 4253451^2 + 2460154^2 .

It is a cyclic number.

It is not a de Polignac number, because 24144203113117 - 219 = 24144202588829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24144203113157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12072101556558 + 12072101556559.

It is an arithmetic number, because the mean of its divisors is an integer number (12072101556559).

Almost surely, 224144203113117 is an apocalyptic number.

It is an amenable number.

24144203113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

24144203113117 is an equidigital number, since it uses as much as digits as its factorization.

24144203113117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 24144203113117 its reverse (71131130244142), we get a palindrome (95275333357259).

The spelling of 24144203113117 in words is "twenty-four trillion, one hundred forty-four billion, two hundred three million, one hundred thirteen thousand, one hundred seventeen".