Base | Representation |
---|---|
bin | 1110001001010000101… |
… | …1001100101100000111 |
3 | 212020020101010221111212 |
4 | 3202110023030230013 |
5 | 12440133024211403 |
6 | 303345021522035 |
7 | 23361604020305 |
oct | 3422413145407 |
9 | 766211127455 |
10 | 243004132103 |
11 | 9406a552147 |
12 | 3b11971331b |
13 | 19bb88a19a5 |
14 | ba9364d275 |
15 | 64c3a694d8 |
hex | 38942ccb07 |
243004132103 has 4 divisors (see below), whose sum is σ = 243005151648. Its totient is φ = 243003112560.
The previous prime is 243004132079. The next prime is 243004132153. The reversal of 243004132103 is 301231400342.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 243004132103 - 210 = 243004131079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243004132153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60098 + ... + 699728.
It is an arithmetic number, because the mean of its divisors is an integer number (60751287912).
Almost surely, 2243004132103 is an apocalyptic number.
243004132103 is a deficient number, since it is larger than the sum of its proper divisors (1019545).
243004132103 is an equidigital number, since it uses as much as digits as its factorization.
243004132103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1019544.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 243004132103 its reverse (301231400342), we get a palindrome (544235532445).
The spelling of 243004132103 in words is "two hundred forty-three billion, four million, one hundred thirty-two thousand, one hundred three".
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