Base | Representation |
---|---|
bin | 1110001001010100110… |
… | …1100111111001011111 |
3 | 212020021120220121121000 |
4 | 3202111031213321133 |
5 | 12440202003420210 |
6 | 303350443041343 |
7 | 23362205023032 |
oct | 3422515477137 |
9 | 766246817530 |
10 | 243021545055 |
11 | 94079365813 |
12 | 3b123510253 |
13 | 19bbc38a703 |
14 | ba95aa3019 |
15 | 64c5358ac0 |
hex | 3895367e5f |
243021545055 has 64 divisors (see below), whose sum is σ = 439436160000. Its totient is φ = 127395192960.
The previous prime is 243021545029. The next prime is 243021545057. The reversal of 243021545055 is 550545120342.
243021545055 is a `hidden beast` number, since 2 + 43 + 0 + 21 + 545 + 0 + 55 = 666.
It is not a de Polignac number, because 243021545055 - 217 = 243021413983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243021545057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12334422 + ... + 12354108.
It is an arithmetic number, because the mean of its divisors is an integer number (6866190000).
Almost surely, 2243021545055 is an apocalyptic number.
243021545055 is a deficient number, since it is larger than the sum of its proper divisors (196414614945).
243021545055 is a wasteful number, since it uses less digits than its factorization.
243021545055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21261 (or 21255 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 36.
Adding to 243021545055 its reverse (550545120342), we get a palindrome (793566665397).
The spelling of 243021545055 in words is "two hundred forty-three billion, twenty-one million, five hundred forty-five thousand, fifty-five".
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