243104011133 has 4 divisors (see below), whose sum is σ = 257404247100. Its totient is φ = 228803775168.

The previous prime is 243104011067. The next prime is 243104011141. The reversal of 243104011133 is 331110401342.

243104011133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 146032508164 + 97071502969 = 382142^2 + 311563^2 .

It is a cyclic number.

It is not a de Polignac number, because 243104011133 - 2¹⁶ = 243103945597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 243104011099 and 243104011108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243104011433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7150117958 + ... + 7150117991.

It is an arithmetic number, because the mean of its divisors is an integer number (64351061775).

Almost surely, 2^243104011133 is an apocalyptic number.

It is an amenable number.

243104011133 is a deficient number, since it is larger than the sum of its proper divisors (14300235967).

243104011133 is a wasteful number, since it uses less digits than its factorization.

243104011133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14300235966.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 243104011133 its reverse (331110401342), we get a palindrome (574214412475).

The spelling of 243104011133 in words is "two hundred forty-three billion, one hundred four million, eleven thousand, one hundred thirty-three".