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243120400535 = 548624080107
BaseRepresentation
bin1110001001101100011…
…0101110100010010111
3212020112110220222211002
43202123012232202113
512440402310304120
6303404333533515
723364515210315
oct3423306564227
9766473828732
10243120400535
119411a145361
123b15064429b
1319c069c028c
14baa4c770b5
1564cdd84375
hex389b1ae897

243120400535 has 4 divisors (see below), whose sum is σ = 291744480648. Its totient is φ = 194496320424.

The previous prime is 243120400499. The next prime is 243120400553. The reversal of 243120400535 is 535004021342.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243120400535 - 214 = 243120384151 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243120400498 and 243120400507.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24312040049 + ... + 24312040058.

It is an arithmetic number, because the mean of its divisors is an integer number (72936120162).

Almost surely, 2243120400535 is an apocalyptic number.

243120400535 is a deficient number, since it is larger than the sum of its proper divisors (48624080113).

243120400535 is an equidigital number, since it uses as much as digits as its factorization.

243120400535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48624080112.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 243120400535 its reverse (535004021342), we get a palindrome (778124421877).

The spelling of 243120400535 in words is "two hundred forty-three billion, one hundred twenty million, four hundred thousand, five hundred thirty-five".

Divisors: 1 5 48624080107 243120400535