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243147131 is a prime number
BaseRepresentation
bin11100111111000…
…10000101111011
3121221112011011022
432133202011323
5444221202011
640043253055
76011500523
oct1637420573
9557464138
10243147131
11115283047
126951a18b
133b4b3456
1424414683
151652d8db
hexe7e217b

243147131 has 2 divisors, whose sum is σ = 243147132. Its totient is φ = 243147130.

The previous prime is 243147127. The next prime is 243147133. The reversal of 243147131 is 131741342.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 243147131 - 22 = 243147127 is a prime.

It is a super-2 number, since 2×2431471312 = 118241054627062322, which contains 22 as substring.

Together with 243147133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 243147131.

It is not a weakly prime, because it can be changed into another prime (243147133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121573565 + 121573566.

It is an arithmetic number, because the mean of its divisors is an integer number (121573566).

Almost surely, 2243147131 is an apocalyptic number.

243147131 is a deficient number, since it is larger than the sum of its proper divisors (1).

243147131 is an equidigital number, since it uses as much as digits as its factorization.

243147131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2016, while the sum is 26.

The square root of 243147131 is about 15593.1757830148. The cubic root of 243147131 is about 624.1510658728.

Adding to 243147131 its reverse (131741342), we get a palindrome (374888473).

The spelling of 243147131 in words is "two hundred forty-three million, one hundred forty-seven thousand, one hundred thirty-one".