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244468013351 is a prime number
BaseRepresentation
bin1110001110101101101…
…1011101100100100111
3212101000101200211001212
43203223123131210213
513001132302411401
6304150153542035
723443100553542
oct3435333354447
9771011624055
10244468013351
1194750902861
123b467a1491b
131a08cc58c03
14bb91c2d859
15655c32bdbb
hex38eb6dd927

244468013351 has 2 divisors, whose sum is σ = 244468013352. Its totient is φ = 244468013350.

The previous prime is 244468013287. The next prime is 244468013353. The reversal of 244468013351 is 153310864442.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 244468013351 - 26 = 244468013287 is a prime.

Together with 244468013353, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 244468013299 and 244468013308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (244468013353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122234006675 + 122234006676.

It is an arithmetic number, because the mean of its divisors is an integer number (122234006676).

Almost surely, 2244468013351 is an apocalyptic number.

244468013351 is a deficient number, since it is larger than the sum of its proper divisors (1).

244468013351 is an equidigital number, since it uses as much as digits as its factorization.

244468013351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 41.

Adding to 244468013351 its reverse (153310864442), we get a palindrome (397778877793).

The spelling of 244468013351 in words is "two hundred forty-four billion, four hundred sixty-eight million, thirteen thousand, three hundred fifty-one".