Base | Representation |
---|---|
bin | 1110010011001111011… |
… | …0110001001001001101 |
3 | 212111011002011012001122 |
4 | 3210303312301021031 |
5 | 13011124340142312 |
6 | 304510522050325 |
7 | 23515154104505 |
oct | 3446366611115 |
9 | 774132135048 |
10 | 245683130957 |
11 | 952147a4690 |
12 | 3b7469499a5 |
13 | 1a224914404 |
14 | bc69376a05 |
15 | 65cdd51b72 |
hex | 3933db124d |
245683130957 has 16 divisors (see below), whose sum is σ = 294390443520. Its totient is φ = 202393422000.
The previous prime is 245683130873. The next prime is 245683130989. The reversal of 245683130957 is 759031386542.
It is a happy number.
It is not a de Polignac number, because 245683130957 - 28 = 245683130701 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 245683130899 and 245683130908.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245683133957) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25549919 + ... + 25559532.
It is an arithmetic number, because the mean of its divisors is an integer number (18399402720).
It is a 1-persistent number, because it is pandigital, but 2⋅245683130957 = 491366261914 is not.
Almost surely, 2245683130957 is an apocalyptic number.
It is an amenable number.
245683130957 is a deficient number, since it is larger than the sum of its proper divisors (48707312563).
245683130957 is a wasteful number, since it uses less digits than its factorization.
245683130957 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51109504.
The product of its (nonzero) digits is 5443200, while the sum is 53.
The spelling of 245683130957 in words is "two hundred forty-five billion, six hundred eighty-three million, one hundred thirty thousand, nine hundred fifty-seven".
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