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250130035 = 5101495307
BaseRepresentation
bin11101110100010…
…10111001110011
3122102122220220101
432322022321303
51003013130120
640453053231
76125033041
oct1672127163
9572586811
10250130035
11119212441
126b927217
133ca8994c
1425311391
1516e5c90a
hexee8ae73

250130035 has 8 divisors (see below), whose sum is σ = 303128496. Its totient is φ = 198122400.

The previous prime is 250130021. The next prime is 250130051. The reversal of 250130035 is 530031052.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 250130035 - 225 = 216575603 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 250129994 and 250130021.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 247149 + ... + 248158.

It is an arithmetic number, because the mean of its divisors is an integer number (37891062).

Almost surely, 2250130035 is an apocalyptic number.

250130035 is a deficient number, since it is larger than the sum of its proper divisors (52998461).

250130035 is a wasteful number, since it uses less digits than its factorization.

250130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 495413.

The product of its (nonzero) digits is 450, while the sum is 19.

The square root of 250130035 is about 15815.4998340236. The cubic root of 250130035 is about 630.0697285717.

Adding to 250130035 its reverse (530031052), we get a palindrome (780161087).

The spelling of 250130035 in words is "two hundred fifty million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 101 505 495307 2476535 50026007 250130035