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25032828300055 = 55006565660011
BaseRepresentation
bin1011011000100011010001…
…10101101010101100010111
310021122010002211211001201221
411230101220311222230113
511240114213021100210
6125123531135031211
75162363551516462
oct554215065525427
9107563084731657
1025032828300055
117a813a9a75294
12298364366b507
1310c777c698604
1462784991c2d9
152d626465b1da
hex16c468d6ab17

25032828300055 has 4 divisors (see below), whose sum is σ = 30039393960072. Its totient is φ = 20026262640040.

The previous prime is 25032828300023. The next prime is 25032828300083. The reversal of 25032828300055 is 55000382823052.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 25032828300055 - 25 = 25032828300023 is a prime.

It is a super-2 number, since 2×250328283000552 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25032828299984 and 25032828300020.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2503282830001 + ... + 2503282830010.

It is an arithmetic number, because the mean of its divisors is an integer number (7509848490018).

Almost surely, 225032828300055 is an apocalyptic number.

25032828300055 is a deficient number, since it is larger than the sum of its proper divisors (5006565660017).

25032828300055 is an equidigital number, since it uses as much as digits as its factorization.

25032828300055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5006565660016.

The product of its (nonzero) digits is 576000, while the sum is 43.

The spelling of 25032828300055 in words is "twenty-five trillion, thirty-two billion, eight hundred twenty-eight million, three hundred thousand, fifty-five".

Divisors: 1 5 5006565660011 25032828300055