251113 has 4 divisors (see below), whose sum is σ = 252928. Its totient is φ = 249300.

The previous prime is 251099. The next prime is 251117. The reversal of 251113 is 311152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 251113 - 2⁵ = 251081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 251093 and 251102.

It is not an unprimeable number, because it can be changed into a prime (251117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 681 + ... + 982.

It is an arithmetic number, because the mean of its divisors is an integer number (63232).

2²⁵¹¹¹³ is an apocalyptic number.

It is an amenable number.

251113 is a deficient number, since it is larger than the sum of its proper divisors (1815).

251113 is a wasteful number, since it uses less digits than its factorization.

251113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1814.

The product of its digits is 30, while the sum is 13.

The square root of 251113 is about 501.1117639809. Note that the first 3 decimals coincide. The cubic root of 251113 is about 63.0894002453.

Adding to 251113 its reverse (311152), we get a palindrome (562265).

It can be divided in two parts, 2 and 51113, that added together give a palindrome (51115).

The spelling of 251113 in words is "two hundred fifty-one thousand, one hundred thirteen".