25113231044131 has 4 divisors (see below), whose sum is σ = 25127175094264. Its totient is φ = 25099286994000.

The previous prime is 25113231044071. The next prime is 25113231044173. The reversal of 25113231044131 is 13144013231152.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25113231044131 - 2⁹ = 25113231043619 is a prime.

It is a super-2 number, since 2×25113231044131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25113231044093 and 25113231044102.

It is not an unprimeable number, because it can be changed into a prime (25113231044431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6972022365 + ... + 6972025966.

It is an arithmetic number, because the mean of its divisors is an integer number (6281793773566).

Almost surely, 2^{25113231044131} is an apocalyptic number.

25113231044131 is a deficient number, since it is larger than the sum of its proper divisors (13944050133).

25113231044131 is a wasteful number, since it uses less digits than its factorization.

25113231044131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13944050132.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 25113231044131 its reverse (13144013231152), we get a palindrome (38257244275283).

The spelling of 25113231044131 in words is "twenty-five trillion, one hundred thirteen billion, two hundred thirty-one million, forty-four thousand, one hundred thirty-one".