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25114100000 = 25551117279
BaseRepresentation
bin10111011000111010…
…101100000100100000
32101211020121110120212
4113120322230010200
5402413202200000
615312014153252
71546231220303
oct273072540440
971736543525
1025114100000
11a718289050
124a4a7b2828
1324a3075b02
1413035a8b3a
159bec0ec35
hex5d8eac120

25114100000 has 432 divisors, whose sum is σ = 72524108160. Its totient is φ = 8486400000.

The previous prime is 25114099999. The next prime is 25114100047. The reversal of 25114100000 is 141152.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 317899961 + ... + 317900039.

It is an arithmetic number, because the mean of its divisors is an integer number (167879880).

Almost surely, 225114100000 is an apocalyptic number.

25114100000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 25114100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (36262054080).

25114100000 is an abundant number, since it is smaller than the sum of its proper divisors (47410008160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

25114100000 is an equidigital number, since it uses as much as digits as its factorization.

25114100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159 (or 114 counting only the distinct ones).

The product of its (nonzero) digits is 40, while the sum is 14.

Adding to 25114100000 its reverse (141152), we get a palindrome (25114241152).

The spelling of 25114100000 in words is "twenty-five billion, one hundred fourteen million, one hundred thousand".