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25130005 = 55026001
BaseRepresentation
bin101111111011…
…1010000010101
31202021201212221
41133313100111
522413130010
62254342341
7423413215
oct137672025
952251787
1025130005
11132045aa
1284ba9b1
13528b434
1434a2245
152315dda
hex17f7415

25130005 has 4 divisors (see below), whose sum is σ = 30156012. Its totient is φ = 20104000.

The previous prime is 25129999. The next prime is 25130011. The reversal of 25130005 is 50003152.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (25129999) and next prime (25130011).

It can be written as a sum of positive squares in 2 ways, for example, as 4418404 + 20711601 = 2102^2 + 4551^2 .

It is not a de Polignac number, because 25130005 - 27 = 25129877 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2512996 + ... + 2513005.

It is an arithmetic number, because the mean of its divisors is an integer number (7539003).

Almost surely, 225130005 is an apocalyptic number.

It is an amenable number.

25130005 is a deficient number, since it is larger than the sum of its proper divisors (5026007).

25130005 is an equidigital number, since it uses as much as digits as its factorization.

25130005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5026006.

The product of its (nonzero) digits is 150, while the sum is 16.

The square root of 25130005 is about 5012.9836425027. The cubic root of 25130005 is about 292.9077470130.

Adding to 25130005 its reverse (50003152), we get a palindrome (75133157).

The spelling of 25130005 in words is "twenty-five million, one hundred thirty thousand, five".

Divisors: 1 5 5026001 25130005