25130011 has 2 divisors, whose sum is σ = 25130012. Its totient is φ = 25130010.

The previous prime is 25129999. The next prime is 25130023. The reversal of 25130011 is 11003152.

It is a balanced prime because it is at equal distance from previous prime (25129999) and next prime (25130023).

It is a cyclic number.

It is not a de Polignac number, because 25130011 - 2²¹ = 23032859 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 25129973 and 25130000.

It is not a weakly prime, because it can be changed into another prime (25130051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565005 + 12565006.

It is an arithmetic number, because the mean of its divisors is an integer number (12565006).

Almost surely, 2^25130011 is an apocalyptic number.

25130011 is a deficient number, since it is larger than the sum of its proper divisors (1).

25130011 is an equidigital number, since it uses as much as digits as its factorization.

25130011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 25130011 is about 5012.9842409487. The cubic root of 25130011 is about 292.9077703244.

Adding to 25130011 its reverse (11003152), we get a palindrome (36133163).

The spelling of 25130011 in words is "twenty-five million, one hundred thirty thousand, eleven".