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2513028311 is a prime number
BaseRepresentation
bin1001010111001001…
…1100010011010111
320111010201001202122
42111302130103113
520121313401221
61053210530155
7116163250103
oct22562342327
96433631678
102513028311
11107a5a2402
125a173695b
13310841501
1419ba82903
15ea950eab
hex95c9c4d7

2513028311 has 2 divisors, whose sum is σ = 2513028312. Its totient is φ = 2513028310.

The previous prime is 2513028307. The next prime is 2513028313. The reversal of 2513028311 is 1138203152.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2513028311 - 22 = 2513028307 is a prime.

It is a super-2 number, since 2×25130283112 = 12630622583775025442, which contains 22 as substring.

Together with 2513028313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2513028313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256514155 + 1256514156.

It is an arithmetic number, because the mean of its divisors is an integer number (1256514156).

Almost surely, 22513028311 is an apocalyptic number.

2513028311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513028311 is an equidigital number, since it uses as much as digits as its factorization.

2513028311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 2513028311 is about 50130.1138139542. The cubic root of 2513028311 is about 1359.5623431348.

The spelling of 2513028311 in words is "two billion, five hundred thirteen million, twenty-eight thousand, three hundred eleven".