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251320000031 is a prime number
BaseRepresentation
bin1110101000001111010…
…1101101111000011111
3220000200220220210202022
43222003311231320133
513104200410000111
6311242123450355
724104641516232
oct3520365557037
9800626823668
10251320000031
1197647651871
124085a6869bb
131a9126aa2b9
14c241c5b419
15680db5a2db
hex3a83d6de1f

251320000031 has 2 divisors, whose sum is σ = 251320000032. Its totient is φ = 251320000030.

The previous prime is 251319999991. The next prime is 251320000049. The reversal of 251320000031 is 130000023152.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 251320000031 - 218 = 251319737887 is a prime.

It is a super-2 number, since 2×2513200000312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 251319999964 and 251320000009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (251320000931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125660000015 + 125660000016.

It is an arithmetic number, because the mean of its divisors is an integer number (125660000016).

Almost surely, 2251320000031 is an apocalyptic number.

251320000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

251320000031 is an equidigital number, since it uses as much as digits as its factorization.

251320000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 17.

Adding to 251320000031 its reverse (130000023152), we get a palindrome (381320023183).

The spelling of 251320000031 in words is "two hundred fifty-one billion, three hundred twenty million, thirty-one", and thus it is an aban number.