25138689407 has 4 divisors (see below), whose sum is σ = 27072434760. Its totient is φ = 23204944056.

The previous prime is 25138689349. The next prime is 25138689419. The reversal of 25138689407 is 70498683152.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25138689407 - 2⁶ = 25138689343 is a prime.

It is a super-2 number, since 2×25138689407² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25138689487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 966872657 + ... + 966872682.

It is an arithmetic number, because the mean of its divisors is an integer number (6768108690).

It is a 1-persistent number, because it is pandigital, but 2⋅25138689407 = 50277378814 is not.

Almost surely, 2^25138689407 is an apocalyptic number.

25138689407 is a deficient number, since it is larger than the sum of its proper divisors (1933745353).

25138689407 is a wasteful number, since it uses less digits than its factorization.

25138689407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1933745352.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 25138689407 in words is "twenty-five billion, one hundred thirty-eight million, six hundred eighty-nine thousand, four hundred seven".