Base | Representation |
---|---|
bin | 1011011011101010110010… |
… | …01000011111010100000010 |
3 | 10022000100120120110102122200 |
4 | 11231311121020133110002 |
5 | 11243343043334343442 |
6 | 125245043432414030 |
7 | 5203205060343540 |
oct | 555653110372402 |
9 | 108010516412580 |
10 | 25139938981122 |
11 | 8012874181309 |
12 | 29a0356847316 |
13 | 11048bc3c4334 |
14 | 62cacb0aad90 |
15 | 2d8e32c7434c |
hex | 16dd5921f502 |
25139938981122 has 96 divisors (see below), whose sum is σ = 67520754572544. Its totient is φ = 6595433856000.
The previous prime is 25139938981117. The next prime is 25139938981147. The reversal of 25139938981122 is 22118983993152.
25139938981122 is a `hidden beast` number, since 2 + 5 + 1 + 399 + 38 + 98 + 1 + 122 = 666.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a self number, because there is not a number n which added to its sum of digits gives 25139938981122.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 143042254 + ... + 143217897.
It is an arithmetic number, because the mean of its divisors is an integer number (703341193464).
Almost surely, 225139938981122 is an apocalyptic number.
25139938981122 is an abundant number, since it is smaller than the sum of its proper divisors (42380815591422).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
25139938981122 is a wasteful number, since it uses less digits than its factorization.
25139938981122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 286260224 (or 286260221 counting only the distinct ones).
The product of its digits is 16796160, while the sum is 63.
The spelling of 25139938981122 in words is "twenty-five trillion, one hundred thirty-nine billion, nine hundred thirty-eight million, nine hundred eighty-one thousand, one hundred twenty-two".
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