Base | Representation |
---|---|
bin | 11110000011000… |
… | …10001100010001 |
3 | 122120021222220121 |
4 | 33001202030101 |
5 | 1004011413213 |
6 | 41002310241 |
7 | 6150323032 |
oct | 1701421421 |
9 | 576258817 |
10 | 252060433 |
11 | 11a310809 |
12 | 704b8381 |
13 | 402b44b1 |
14 | 25694a89 |
15 | 171de88d |
hex | f062311 |
252060433 has 2 divisors, whose sum is σ = 252060434. Its totient is φ = 252060432.
The previous prime is 252060379. The next prime is 252060439. The reversal of 252060433 is 334060252.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 233111824 + 18948609 = 15268^2 + 4353^2 .
It is a cyclic number.
It is not a de Polignac number, because 252060433 - 217 = 251929361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 252060398 and 252060407.
It is not a weakly prime, because it can be changed into another prime (252060439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126030216 + 126030217.
It is an arithmetic number, because the mean of its divisors is an integer number (126030217).
Almost surely, 2252060433 is an apocalyptic number.
It is an amenable number.
252060433 is a deficient number, since it is larger than the sum of its proper divisors (1).
252060433 is an equidigital number, since it uses as much as digits as its factorization.
252060433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
The square root of 252060433 is about 15876.4112128655. The cubic root of 252060433 is about 631.6864473384.
The spelling of 252060433 in words is "two hundred fifty-two million, sixty thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •